Tension Force Calculator
Calculate rope tension for hanging masses, vertically accelerating objects, and Atwood machines.
How it works
- 1Choose a scenario — hanging at rest, vertical acceleration, or Atwood machine — then enter the mass values.
- 2Each input is converted to SI (kg, m/s²) before the dynamics core applies the exact tension formula for that scenario.
- 3The result is converted back to your chosen unit system and displayed alongside the governing formula.
Use cases
- Engineering and physics homework — verify rope tensions in pulley and elevator problems.
- Rigging and lifting — estimate the load on a rope or cable supporting a stationary or accelerating object.
- Lab pre-work — predict Atwood machine behaviour (acceleration and tension) before running the experiment.
Frequently asked questions
What is the tension in a rope holding a stationary hanging mass?
T = mg, where m is the mass in kilograms and g ≈ 9.81 m/s². For example, a 5 kg mass hanging at rest gives T = 5 × 9.81 ≈ 49 N.
How does vertical acceleration affect rope tension?
T = m(g + a). When a lift accelerates upward (a > 0) the rope carries extra load, so tension rises above mg. Downward acceleration (a < 0) reduces it — in free fall (a = −g) the tension drops to zero.
What is the Atwood machine tension formula?
For two masses over a frictionless pulley: T = 2m₁m₂g ÷ (m₁ + m₂), and the acceleration is a = |m₁ − m₂|g ÷ (m₁ + m₂). With m₁ = 3 kg and m₂ = 5 kg: T ≈ 36.8 N and a ≈ 2.45 m/s².
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